python实现一组典型数据格式转换

脚本专栏 2025/4/30 佚名

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本文实例为大家分享了一组典型数据格式转换的python实现代码，供大家参考，具体内容如下

有一组源数据，第一行会是个日期数据，第二行标明字段，再接下来是两行数据行。

1018 14:31:30.193
Type Succ Fail
sour_sm 1308 1205
data_sm 2205 3301
1019 16:32:30.201
Type Succ Fail
data_sm 3308 2206
data_sm 1765 1105
1020 18:00:00.203
Type Succ Fail
sour_sm 7804 1105
data_sm 2976 1300

要转换成数据

Time Type Succ Fail Total
1018 14:31:30.193 sour_sm 1308 1205 2513
1018 14:31:30.193 data_sm 2205 3301 5506
1019 16:32:30.201 data_sm 3308 2206 5514
1019 16:32:30.201 data_sm 1765 1105 2870
1020 18:00:00.203 sour_sm 7804 1105 8909
1020 18:00:00.203 data_sm 2976 1300 4276

这个时候可以使用Python来处理，代码如下:

# coding = utf-8
fd = open(r"output.txt", "w", encoding="utf-8")
fd.write("%s\t\t\t\t%s\t%s\t%s\t%s\n" % ("Time", "Type", "Succ", "Fail", "Total"))
 
with open(r"data.txt", "r", encoding="utf-8") as fd1:
 lines = fd1.readlines()
 time1 = lines[0::4]
 data1 = lines[2::4]
 data2 = lines[3::4]
 for (i, line) in enumerate(time1):
 Time = line.strip()
 Type_1 = data1[i].strip().split()[0]
 Succ_1 = data1[i].strip().split()[1]
 Fail_1 = data1[i].strip().split()[2]
 Total_1 = str(int(Succ_1) + int(Fail_1))
 Type_2 = data2[i].strip().split()[0]
 Succ_2 = data2[i].strip().split()[1]
 Fail_2 = data2[i].strip().split()[2]
 Total_2 = str(int(Succ_2) + int(Fail_2))
 fd.write("%s\t%s\t%s\t%s\t%s\n" % (Time, Type_1, Succ_1, Fail_1, Total_1))
 fd.write("%s\t%s\t%s\t%s\t%s\n" % (Time, Type_2, Succ_2, Fail_2, Total_2))
fd.close()

生成文件格式如下，基本上满足了需求。