import os
printos.path.splitext("path_to_file")[0]
 
from os.path import basename
# now you can call it directly with basename
print basename("/a/b/c.txt")
 
>base=os.path.basename('/root/dir/sub/file.ext')
> base
'file.ext'
> os.path.splitext(base)
('file', '.ext')
> os.path.splitext(base)[0]
'file'
> 
> printos.path.splitext(os.path.basename("hemanth.txt"))[0]
hemanth
> file ='/root/dir/sub.exten/file.data.1.2.dat'
> print('.').join(file.split('.')[:-1])
/root/dir/sub.exten/file.data.1.2
 
> s = 'c:\\temp\\akarmi.txt'
> print(os.path.splitext(s)[0])
c:\temp\akarmi
因此，我不需要驱动器号或者目录名，我使用：
 
>print(os.path.splitext(os.path.basename(s))[0])
akarmi
def getFileNameWithoutExtension(path):
 returnpath.split('\\').pop().split('/').pop().rsplit('.', 1)[0]
 
getFileNameWithoutExtension('/path/to/file-0.0.1.ext')
# => file-0.0.1
 
getFileNameWithoutExtension('\\path\\to\\file-0.0.1.ext')
# => file-0.0.1