蝙蝠岛资源网 Design By www.hbtsch.com
CREATE TABLE table1( [ID] [bigint] IDENTITY(1,1) NOT NULL, [Name] [nvarchar](128) NOT NULL, [class] int not null, [date] datetime not null)class 表示分类编号。 分类数不固定, 至少有上千种分类
date 表示该条记录被更新的时间
我们现在想获得每个分类最新被更新的5条记录。
解决方案
select id,name,class,date from(select id,name,class,date ,row_number() over(partition by class order by date desc)as rowindex from table1) awhere rowindex <= 5
create table #temp
(
company varchar(50),
product varchar(50),
inputDate datetime
)
insert into #temp(company,product,inputDate) values('杭州大明有限公司','汽车1','2010-8-1')
insert into #temp(company,product,inputDate) values('杭州大明有限公司','汽车2','2010-8-1')
insert into #temp(company,product,inputDate) values('杭州大明有限公司','汽车3','2010-8-1')
insert into #temp(company,product,inputDate) values('杭州大明有限公司','汽车4','2010-8-1')
insert into #temp(company,product,inputDate) values('杭州大明有限公司','汽车5','2010-7-1')
insert into #temp(company,product,inputDate) values('北京小科有限公司','汽车1','2010-8-1')
insert into #temp(company,product,inputDate) values('北京小科有限公司','汽车2','2010-8-1')
insert into #temp(company,product,inputDate) values('北京小科有限公司','汽车3','2010-8-1')
insert into #temp(company,product,inputDate) values('北京小科有限公司','汽车4','2010-8-1')
insert into #temp(company,product,inputDate) values('上海有得有限公司','汽车1','2010-8-1')
insert into #temp(company,product,inputDate) values('上海有得有限公司','汽车2','2010-8-1')
insert into #temp(company,product,inputDate) values('上海有得有限公司','汽车3','2010-8-1')
insert into #temp(company,product,inputDate) values('上海有得有限公司','汽车4','2010-8-1')
insert into #temp(company,product,inputDate) values('天津旺旺有限公司','汽车4','2010-8-1')
insert into #temp(company,product,inputDate) values('天津旺旺有限公司','汽车5','2010-8-1')
select * from #temp
create proc getdata
@num int
as
begin
select top 4 * from
(
select ( select count(*) from #temp where company=a.company and product<=a.product) as 序号,a.company,a.product,a.inputDate
from #temp a
) b
where 序号>=@num
order by 序号,inputDate desc
end
go
getdata 2
/*
结果
1 杭州大明有限公司 汽车1 2010-08-01 00:00:00.000
1 北京小科有限公司 汽车1 2010-08-01 00:00:00.000
1 上海有得有限公司 汽车1 2010-08-01 00:00:00.000
1 天津旺旺有限公司 汽车4 2010-08-01 00:00:00.000
2 天津旺旺有限公司 汽车5 2010-08-01 00:00:00.000
2 上海有得有限公司 汽车2 2010-08-01 00:00:00.000
2 北京小科有限公司 汽车2 2010-08-01 00:00:00.000
2 杭州大明有限公司 汽车2 2010-08-01 00:00:00.000
3 杭州大明有限公司 汽车3 2010-08-01 00:00:00.000
3 北京小科有限公司 汽车3 2010-08-01 00:00:00.000
3 上海有得有限公司 汽车3 2010-08-01 00:00:00.000
4 北京小科有限公司 汽车4 2010-08-01 00:00:00.000
4 北京小科有限公司 汽车4 2010-08-01 00:00:00.000
4 上海有得有限公司 汽车4 2010-08-01 00:00:00.000
4 杭州大明有限公司 汽车4 2010-08-01 00:00:00.000
5 杭州大明有限公司 汽车5 2010-07-01 00:00:00.000
*/
--sql2005
create proc getdata2005
@num int
as
begin
select top 4 * from
(
select row_number() over (partition by company order by product ) as 序号,a.company,a.product,a.inputDate
from #temp a
) b
where 序号>=@num
order by 序号,inputDate desc
end
getdata2005 4
select * from #temp
select ( select count(*) from #temp where company+ product<=a.company+a.product) as 序号,a.company,a.product,a.inputDate
,a.company+a.product as 唯一标志一行
from #temp a
order by company,product
复制代码 代码如下:
Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->if object_id(N'company') is not null
drop table company
go
create table company
(
companyname varchar(2),
product varchar(60)
)
--公司1
insert into company
select 'A','A1' union
select 'A','A2' union
select 'A','A3' union
select 'A','A4' union
select 'A','A5' union
select 'A','A6' union
select 'A','A7' union
select 'A','A8' union
select 'A','A9' union
select 'A','A10'
--公司2
insert into company
select 'B','B1' union
select 'B','B2' union
select 'B','B3' union
select 'B','B4' union
select 'B','B5' union
select 'B','B6' union
select 'B','B7' union
select 'B','B8' union
select 'B','B9' union
select 'B','B10'
--公司3
insert into company
select 'C','C1' union
select 'C','C2' union
select 'C','C3' union
select 'C','C4' union
select 'C','C5' union
select 'C','C6' union
select 'C','C7' union
select 'C','C8' union
select 'C','C9' union
select 'C','C10'
--公司4
insert into company
select 'D','D1' union
select 'D','D2' union
select 'D','D3' union
select 'D','D4' union
select 'D','D5' union
select 'D','D6' union
select 'D','D7' union
select 'D','D8' union
select 'D','D9' union
select 'D','D10'
--公司5
insert into company
select 'E','E1' union
select 'E','E2' union
select 'E','E3' union
select 'E','E4' union
select 'E','E5' union
select 'E','E6' union
select 'E','E7' union
select 'E','E8' union
select 'E','E9' union
select 'E','E10'
--公司6
insert into company
select 'F','F1' union
select 'F','F2' union
select 'F','F3' union
select 'F','F4' union
select 'F','F5' union
select 'F','F6' union
select 'F','F7' union
select 'F','F8' union
select 'F','F9' union
select 'F','F10'
--公司7
insert into company
select 'G','G1' union
select 'G','G2' union
select 'G','G3' union
select 'G','G4' union
select 'G','G5' union
select 'G','G6' union
select 'G','G7' union
select 'G','G8' union
select 'G','G9' union
select 'G','G10'
--公司8
insert into company
select 'H','H1' union
select 'H','H2' union
select 'H','H3' union
select 'H','H4' union
select 'H','H5' union
select 'H','H6' union
select 'H','H7' union
select 'H','H8' union
select 'H','H9' union
select 'H','H10'
--公司9
insert into company
select 'I','I1' union
select 'I','I2' union
select 'I','I3' union
select 'I','I4' union
select 'I','I5' union
select 'I','I6' union
select 'I','I7' union
select 'I','I8' union
select 'I','I9' union
select 'I','I10'
--公司10
insert into company
select 'J','J1' union
select 'J','J2' union
select 'J','J3' union
select 'J','J4' union
select 'J','J5' union
select 'J','J6' union
select 'J','J7' union
select 'J','J8' union
select 'J','J9' union
select 'J','J10'
IF (select Object_id('Tempdb..#t')) IS NULL
select identity(int,1,1) as id,* into #t from company
order by left(product,1),cast(substring(product,2,2) as int)
if object_id(N'getdata','P') is not null
drop table getdata
go
create proc getdata
@num1 int --第几页
as
begin
select companyname,product from
(
select row_number() over (partition by companyname order by id) as 序号,*
from #t
) a
where 序号=@num1
order by companyname
end
go
getdata 4
go
DROP procedure getdata
date 表示该条记录被更新的时间
我们现在想获得每个分类最新被更新的5条记录。
解决方案
select id,name,class,date from(select id,name,class,date ,row_number() over(partition by class order by date desc)as rowindex from table1) awhere rowindex <= 5
create table #temp
(
company varchar(50),
product varchar(50),
inputDate datetime
)
insert into #temp(company,product,inputDate) values('杭州大明有限公司','汽车1','2010-8-1')
insert into #temp(company,product,inputDate) values('杭州大明有限公司','汽车2','2010-8-1')
insert into #temp(company,product,inputDate) values('杭州大明有限公司','汽车3','2010-8-1')
insert into #temp(company,product,inputDate) values('杭州大明有限公司','汽车4','2010-8-1')
insert into #temp(company,product,inputDate) values('杭州大明有限公司','汽车5','2010-7-1')
insert into #temp(company,product,inputDate) values('北京小科有限公司','汽车1','2010-8-1')
insert into #temp(company,product,inputDate) values('北京小科有限公司','汽车2','2010-8-1')
insert into #temp(company,product,inputDate) values('北京小科有限公司','汽车3','2010-8-1')
insert into #temp(company,product,inputDate) values('北京小科有限公司','汽车4','2010-8-1')
insert into #temp(company,product,inputDate) values('上海有得有限公司','汽车1','2010-8-1')
insert into #temp(company,product,inputDate) values('上海有得有限公司','汽车2','2010-8-1')
insert into #temp(company,product,inputDate) values('上海有得有限公司','汽车3','2010-8-1')
insert into #temp(company,product,inputDate) values('上海有得有限公司','汽车4','2010-8-1')
insert into #temp(company,product,inputDate) values('天津旺旺有限公司','汽车4','2010-8-1')
insert into #temp(company,product,inputDate) values('天津旺旺有限公司','汽车5','2010-8-1')
select * from #temp
create proc getdata
@num int
as
begin
select top 4 * from
(
select ( select count(*) from #temp where company=a.company and product<=a.product) as 序号,a.company,a.product,a.inputDate
from #temp a
) b
where 序号>=@num
order by 序号,inputDate desc
end
go
getdata 2
/*
结果
1 杭州大明有限公司 汽车1 2010-08-01 00:00:00.000
1 北京小科有限公司 汽车1 2010-08-01 00:00:00.000
1 上海有得有限公司 汽车1 2010-08-01 00:00:00.000
1 天津旺旺有限公司 汽车4 2010-08-01 00:00:00.000
2 天津旺旺有限公司 汽车5 2010-08-01 00:00:00.000
2 上海有得有限公司 汽车2 2010-08-01 00:00:00.000
2 北京小科有限公司 汽车2 2010-08-01 00:00:00.000
2 杭州大明有限公司 汽车2 2010-08-01 00:00:00.000
3 杭州大明有限公司 汽车3 2010-08-01 00:00:00.000
3 北京小科有限公司 汽车3 2010-08-01 00:00:00.000
3 上海有得有限公司 汽车3 2010-08-01 00:00:00.000
4 北京小科有限公司 汽车4 2010-08-01 00:00:00.000
4 北京小科有限公司 汽车4 2010-08-01 00:00:00.000
4 上海有得有限公司 汽车4 2010-08-01 00:00:00.000
4 杭州大明有限公司 汽车4 2010-08-01 00:00:00.000
5 杭州大明有限公司 汽车5 2010-07-01 00:00:00.000
*/
--sql2005
create proc getdata2005
@num int
as
begin
select top 4 * from
(
select row_number() over (partition by company order by product ) as 序号,a.company,a.product,a.inputDate
from #temp a
) b
where 序号>=@num
order by 序号,inputDate desc
end
getdata2005 4
select * from #temp
select ( select count(*) from #temp where company+ product<=a.company+a.product) as 序号,a.company,a.product,a.inputDate
,a.company+a.product as 唯一标志一行
from #temp a
order by company,product
复制代码 代码如下:
Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->if object_id(N'company') is not null
drop table company
go
create table company
(
companyname varchar(2),
product varchar(60)
)
--公司1
insert into company
select 'A','A1' union
select 'A','A2' union
select 'A','A3' union
select 'A','A4' union
select 'A','A5' union
select 'A','A6' union
select 'A','A7' union
select 'A','A8' union
select 'A','A9' union
select 'A','A10'
--公司2
insert into company
select 'B','B1' union
select 'B','B2' union
select 'B','B3' union
select 'B','B4' union
select 'B','B5' union
select 'B','B6' union
select 'B','B7' union
select 'B','B8' union
select 'B','B9' union
select 'B','B10'
--公司3
insert into company
select 'C','C1' union
select 'C','C2' union
select 'C','C3' union
select 'C','C4' union
select 'C','C5' union
select 'C','C6' union
select 'C','C7' union
select 'C','C8' union
select 'C','C9' union
select 'C','C10'
--公司4
insert into company
select 'D','D1' union
select 'D','D2' union
select 'D','D3' union
select 'D','D4' union
select 'D','D5' union
select 'D','D6' union
select 'D','D7' union
select 'D','D8' union
select 'D','D9' union
select 'D','D10'
--公司5
insert into company
select 'E','E1' union
select 'E','E2' union
select 'E','E3' union
select 'E','E4' union
select 'E','E5' union
select 'E','E6' union
select 'E','E7' union
select 'E','E8' union
select 'E','E9' union
select 'E','E10'
--公司6
insert into company
select 'F','F1' union
select 'F','F2' union
select 'F','F3' union
select 'F','F4' union
select 'F','F5' union
select 'F','F6' union
select 'F','F7' union
select 'F','F8' union
select 'F','F9' union
select 'F','F10'
--公司7
insert into company
select 'G','G1' union
select 'G','G2' union
select 'G','G3' union
select 'G','G4' union
select 'G','G5' union
select 'G','G6' union
select 'G','G7' union
select 'G','G8' union
select 'G','G9' union
select 'G','G10'
--公司8
insert into company
select 'H','H1' union
select 'H','H2' union
select 'H','H3' union
select 'H','H4' union
select 'H','H5' union
select 'H','H6' union
select 'H','H7' union
select 'H','H8' union
select 'H','H9' union
select 'H','H10'
--公司9
insert into company
select 'I','I1' union
select 'I','I2' union
select 'I','I3' union
select 'I','I4' union
select 'I','I5' union
select 'I','I6' union
select 'I','I7' union
select 'I','I8' union
select 'I','I9' union
select 'I','I10'
--公司10
insert into company
select 'J','J1' union
select 'J','J2' union
select 'J','J3' union
select 'J','J4' union
select 'J','J5' union
select 'J','J6' union
select 'J','J7' union
select 'J','J8' union
select 'J','J9' union
select 'J','J10'
IF (select Object_id('Tempdb..#t')) IS NULL
select identity(int,1,1) as id,* into #t from company
order by left(product,1),cast(substring(product,2,2) as int)
if object_id(N'getdata','P') is not null
drop table getdata
go
create proc getdata
@num1 int --第几页
as
begin
select companyname,product from
(
select row_number() over (partition by companyname order by id) as 序号,*
from #t
) a
where 序号=@num1
order by companyname
end
go
getdata 4
go
DROP procedure getdata
标签:
分类,最新的几条
蝙蝠岛资源网 Design By www.hbtsch.com
广告合作:本站广告合作请联系QQ:858582 申请时备注:广告合作(否则不回)
免责声明:本站文章均来自网站采集或用户投稿,网站不提供任何软件下载或自行开发的软件! 如有用户或公司发现本站内容信息存在侵权行为,请邮件告知! 858582#qq.com
免责声明:本站文章均来自网站采集或用户投稿,网站不提供任何软件下载或自行开发的软件! 如有用户或公司发现本站内容信息存在侵权行为,请邮件告知! 858582#qq.com
蝙蝠岛资源网 Design By www.hbtsch.com
暂无每个分类取最新的几条的SQL实现代码的评论...
《魔兽世界》大逃杀!60人新游玩模式《强袭风暴》3月21日上线
暴雪近日发布了《魔兽世界》10.2.6 更新内容,新游玩模式《强袭风暴》即将于3月21 日在亚服上线,届时玩家将前往阿拉希高地展开一场 60 人大逃杀对战。
艾泽拉斯的冒险者已经征服了艾泽拉斯的大地及遥远的彼岸。他们在对抗世界上最致命的敌人时展现出过人的手腕,并且成功阻止终结宇宙等级的威胁。当他们在为即将于《魔兽世界》资料片《地心之战》中来袭的萨拉塔斯势力做战斗准备时,他们还需要在熟悉的阿拉希高地面对一个全新的敌人──那就是彼此。在《巨龙崛起》10.2.6 更新的《强袭风暴》中,玩家将会进入一个全新的海盗主题大逃杀式限时活动,其中包含极高的风险和史诗级的奖励。
《强袭风暴》不是普通的战场,作为一个独立于主游戏之外的活动,玩家可以用大逃杀的风格来体验《魔兽世界》,不分职业、不分装备(除了你在赛局中捡到的),光是技巧和战略的强弱之分就能决定出谁才是能坚持到最后的赢家。本次活动将会开放单人和双人模式,玩家在加入海盗主题的预赛大厅区域前,可以从强袭风暴角色画面新增好友。游玩游戏将可以累计名望轨迹,《巨龙崛起》和《魔兽世界:巫妖王之怒 经典版》的玩家都可以获得奖励。
更新日志
2024年12月22日
2024年12月22日
- 小骆驼-《草原狼2(蓝光CD)》[原抓WAV+CUE]
- 群星《欢迎来到我身边 电影原声专辑》[320K/MP3][105.02MB]
- 群星《欢迎来到我身边 电影原声专辑》[FLAC/分轨][480.9MB]
- 雷婷《梦里蓝天HQⅡ》 2023头版限量编号低速原抓[WAV+CUE][463M]
- 群星《2024好听新歌42》AI调整音效【WAV分轨】
- 王思雨-《思念陪着鸿雁飞》WAV
- 王思雨《喜马拉雅HQ》头版限量编号[WAV+CUE]
- 李健《无时无刻》[WAV+CUE][590M]
- 陈奕迅《酝酿》[WAV分轨][502M]
- 卓依婷《化蝶》2CD[WAV+CUE][1.1G]
- 群星《吉他王(黑胶CD)》[WAV+CUE]
- 齐秦《穿乐(穿越)》[WAV+CUE]
- 发烧珍品《数位CD音响测试-动向效果(九)》【WAV+CUE】
- 邝美云《邝美云精装歌集》[DSF][1.6G]
- 吕方《爱一回伤一回》[WAV+CUE][454M]